Please please help me! :((

Question

anonymous · Answer

attachment

hba · Answer

The first step would be to make a diag.

jiteshmeghwal9 · Answer

|dw:1357883876328:dw|

hba · Answer

Now use the pythagoras theorem.

anonymous · Answer

does it matter which place the numbers are used?

hba · Answer

Yes it does.

jiteshmeghwal9 · Answer

Now use Pythagorean theorem

$\LARGE{(a)^2+(b)^2=(h)^2}$
put the values
$(a)^2+(9)^2=(36)^2$
$a=\sqrt{(36)^2-(9)^2}=?$

jiteshmeghwal9 · Answer

Can u solve it for $a$ ?

anonymous · Answer

I should be able to now. One second.. Thanks so much for the help!

jiteshmeghwal9 · Answer

yw :)

hba · Answer

Actually the Pythagoras theorem is,


(Hypotenuse )^2=(perpendicular)^2+(Base)^2

anonymous · Answer

wait...

jiteshmeghwal9 · Answer

yup but i let her understand the Pythagorean theorem according to her question @hba :)

hba · Answer

I know that @jiteshmeghwal9  :)

I was just telling :)

jiteshmeghwal9 · Answer

Ohh! ok sorry :P

anonymous · Answer

do you guys know anywhere on the web that is a good place to learn and practice basic and intermediate geometry ?

hba · Answer

anonymous · Answer

I appreciate it once again. Thanks so much! (: