write a polynomial function in standard form with the given zeros. x=1,-1,-2 please give me the steps
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OpenStudy (anonymous):
work backwards from solving a polynomial for x, if a zero is 1 that means a factor is
(x-1)
-1 is a zero then (x+1) is a factor
and for -2
(x+2) is a factor
so expanding (x-1)(x+2)(x+1) will give you the polynomial
OpenStudy (anonymous):
what else do i do i got stuck there
OpenStudy (anonymous):
foil it out
OpenStudy (anonymous):
i never heard of foil
OpenStudy (anonymous):
Multiply it out, do you know how to multiply
(x-1)*(x+2)
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Ok do that, then multiply your answer by (x+1)
OpenStudy (anonymous):
i multiplied x+1 and x+2 it gave me xˆ2+x+2
OpenStudy (anonymous):
i need help multiply it by x-1
OpenStudy (anonymous):
hello
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OpenStudy (anonymous):
2 should be negative
x^2+x-2
now take every term and multiply it by (x-1)
(x^2+x-2)(x-1)
OpenStudy (anonymous):
why does 2 have to be negative
OpenStudy (anonymous):
because -1*2=-2
OpenStudy (anonymous):
ok thank you so much
OpenStudy (anonymous):
Now what do you get when you multiply
(x^2+x-2)(x-1)
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