Solve the triangle.

B = 73°, b = 15, c = 10
OPTIONS :

C = 39.6°, A = 67.4°, a ≈ 14.5

Cannot be solved

C = 44.8°, A = 62.4°, a ≈ 14.5

C = 39.6°, A = 67.4°, a ≈ 20.3

And
State whether the given measurements determine zero, one, or two triangles.

C = 30°, a = 28, c = 14

One

Zero

Two

PLEASE HELP

Question

Solve the triangle. 

B = 73°, b = 15, c = 10
 OPTIONS :

 C = 39.6°, A = 67.4°, a ≈ 14.5

 Cannot be solved

 C = 44.8°, A = 62.4°, a ≈ 14.5

 C = 39.6°, A = 67.4°, a ≈ 20.3

And 
State whether the given measurements determine zero, one, or two triangles. 

C = 30°, a = 28, c = 14

 One

 Zero

 Two
 
PLEASE HELP

anonymous · Answer

@chme anything ?

campbell_st · Answer

well you can use the rule of sine to find angle C

$$\frac{Sin(B)}{b} = \frac{Sin(C)}{c}... or ... \frac{\sin(73)}{15}= \frac{\sin(C)}{10}$$ 

solve for C

then angle A is found by angle sum of a triangle... 

and side a is found by the rule of sines