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Question

kuoministers · Answer

simplify $$\frac{ 2x }{\sqrt{x}(\sqrt{x + 2} + \sqrt{x})}$$

kuoministers · Answer

$$ \frac{ 2x }{ \sqrt{x ^{2}+ 2x} + \sqrt{x ^{2}}}$$
pls tell me this is right...
im pretty sure i need to rationalise it

kuoministers · Answer

$$\frac{ 2x }{ \sqrt{x ^{2 }+ 2x}+x }$$

anonymous · Answer

you have to distribute √x into (√x+2 + √X) once you do, you lose the radical sign

anonymous · Answer

2x/x^2+2x+x^2

anonymous · Answer

2x/2x^2+2x

anonymous · Answer

2x/2x(x+2)

anonymous · Answer

1/2x

kuoministers · Answer

are you sure the 2x isnt sqrt 2x?

anonymous · Answer

it was, but i factored it out

anonymous · Answer

2x/2x^2+2x

anonymous · Answer

oh crap its 2x/2x(x+1)

anonymous · Answer

not x+2, im sorry. i think you end up 1/x+1

kuoministers · Answer

thats not the answer in the back of the books
$$\sqrt{x^2 + 2x} - x$$
was the answer...

anonymous · Answer

sorry,

kuoministers · Answer

if you squared everything at the denominator wouldnt you do the same on the numerator?

anonymous · Answer

yes, but if you go step by step, the 4x^2 on top will cancel out

anonymous · Answer

are you identifying domains?

anonymous · Answer

what is your chapter called?

kuoministers · Answer

year 11 extension 1 rationalising the denominator

kuoministers · Answer

im from australia NSW

anonymous · Answer

remember doing domains, you only solved the denominator or what was in the radical. its the same thing

anonymous · Answer

radicals have to be greater than or equal to zero, denominators can't equal zero. you basically ignore the numorator unless there is a radical

anonymous · Answer

kuoministers · Answer

haha i completed the quesiton!! thanks for your help!!

kuoministers · Answer

yea thats what the chapter of what i was doing was about

anonymous · Answer

good luck mate