Question

In the figure, ABCD is a cyclic quadrilateral with AD//BC.
(a) Show that PAD is an isosceles triangle.
(b) Hence deduce that AB=DC.

Answer 1

is there any fig of this question ?

Answer 2

angle A = angle C in the same way angle D= angle B cause
....

Answer 3

what is the theorem><

Answer 4

again angle A = angle B and angle D= angle C
cause they are alternate
now derive the relation from these two point and for how and why question plz go through ur book that will give u some concepts

Answer 5

ohh i know. since ABCD is a cyclic quad. and therefore DAB=180-DCB

Answer 6

yep u got it !

Answer 7

but...

Answer 8

how to explain that PAD=PDA

Answer 9

since angle A= angle B= angle D as angle D= angle B and angle B = angle A

Answer 10

PBC=PDA? why?

Answer 11

@Callisto would you kindly help me if you are free?

Answer 12

ohh yes..

Answer 13

PDA=ABC (ext. angle, cyclic quad.)

Answer 14

but why PAD=PDA?