Question

solve y^2-3y=18

Answer 1

Compare it with the standard form.

\[\huge\ ax^2+bx+c=0\]

Answer 2

y^2-3y-18=0
(y-6)(y+3)=0
solve that.

Answer 3

Then use the quad formula.

Answer 4

y^2 -3y - 18=0
try rational root theorem! ;)

Answer 5

factors of 18 = +- (1,2,3,6,9,18)

Answer 6

so it would be y\[y^2-3y-18=0 ?\]

Answer 7

Yes :)

Answer 8

yaaaaayy ! i got it !

Answer 9

What did ya get ?

Answer 10

it was asking me to solve for y
and i had to factor which was y=6 y=-3

Answer 11

Very good,You nailed it right.

When i am not around you can check by putting the values in your actual ques and check if


LHS=RHS :)

Answer 12

If LHS=RHS then your answer is correct :)

Answer 13

thank you soo much . im studying for SAT

Answer 14

Oh great,Best of luck with that :)

I never knew such easy questions appeared in the SAT