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Mathematics 16 Online
OpenStudy (anonymous):

Solve the equation. Check for extraneous solutions. A. x = 3/2 or x = 5/6 B. x = 3/2 or x = 5/8 C. x = 5/8 D. x = 3/2

OpenStudy (anonymous):

hero (hero):

Hint: Check for extraneous solutions first.

OpenStudy (anonymous):

is the answer A?

hero (hero):

Did you check both \(\large\frac{3}{2}\) `and` \(\frac{5}{8}\)?

OpenStudy (anonymous):

im sorry , im confused im not quite sure how to work out the answer choices

hero (hero):

Do you know how to check? Suppose you solved x + 5 = 7, and got x = 3. How would you check that?

OpenStudy (anonymous):

no not really, and you would subtract 5 from 7 and get 2

hero (hero):

You check it by substituting the 3 into the equation to see if both sides equal: x + 5 = 7 3 + 5 = 7 8 = 7 False

hero (hero):

You think it x = 2 is correct so let's check that: x + 5 = 7 2 + 5 = 7 7 = 7 True

hero (hero):

That's all you do when checking values

OpenStudy (anonymous):

so just add up whats on the left of my problem and see if it equals?

hero (hero):

you have to substitute the number you want to check first everywhere you see x, then simplify both sides: For example x + 5 = 2x + 4 If I think x = 3, then I will substitute that in everywhere I see x, then evaluate: x + 5 = 2x + 4 3 + 5 = 2(3) + 4 8 = 6 + 4 8 = 10 False

hero (hero):

Do the same with your math problem.

OpenStudy (anonymous):

okay i understand , thanks :)

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