Which of the following is not an equivalent form of the compound inequality

x + 6 13 or x + 6 less than or greater to 11

x 7 or x less than or greater to 5

x less than or greater to 5 or x 7

A number line with an open circle on 7, a closed circle on 5, and shading in between.

A number line with an open circle on 7, shading to the right, and a closed circle on 5, shading to the left.

Question

Which of the following is not an equivalent form of the compound inequality

x + 6 > 13 or x + 6 less than or greater to 11 

 x > 7 or x less than or greater to 5 

 x less than or greater to 5 or x > 7 

 A number line with an open circle on 7, a closed circle on 5, and shading in between. 

 A number line with an open circle on 7, shading to the right, and a closed circle on 5, shading to the left.

aravindg · Answer

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aravindg · Answer

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anonymous · Answer

4th and 5th are not equivalent statements
and 1st ,2nd and 3rd are because x+6>13
                                                    x>13-6
                                                    x>7
and x+6 less than or greater to 11 is same as x+6 less than or greater to 5(as 11-6=5)

anonymous · Answer

@ivandelgado

anonymous · Answer

and 4th means $$5\le x <7$$
and 5th means $$x \le5$$ and x>7

anonymous · Answer

@ivandelgado reply..........

aravindg · Answer

its clear the user is looking only for answers