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Mathematics 14 Online
OpenStudy (anonymous):

Find all solutions in the interval [0, 2π) sec2x - 2 = tan2x

OpenStudy (anonymous):

Hint: 1 + tan^2 x = Sec^2 x

OpenStudy (anonymous):

is it pi/4?

OpenStudy (anonymous):

is that \(sec^{2} x\) or \(sec2x\)?

OpenStudy (anonymous):

sec^2 x

OpenStudy (anonymous):

in that case, use what Yahoo said and simplify...

OpenStudy (anonymous):

is it pi/4?

OpenStudy (anonymous):

wait a minute....is it tan^2 x too?

OpenStudy (anonymous):

something's wrong with your question. you know why? if you convert sec^2 x to 1+tan^2 x, the tan^2x on both sides will cancel giving -1=0 which is absurd.

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