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Find all solutions in the interval [0, 2π) sec2x - 2 = tan2x
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Hint: 1 + tan^2 x = Sec^2 x
is it pi/4?
is that \(sec^{2} x\) or \(sec2x\)?
sec^2 x
in that case, use what Yahoo said and simplify...
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is it pi/4?
wait a minute....is it tan^2 x too?
something's wrong with your question. you know why? if you convert sec^2 x to 1+tan^2 x, the tan^2x on both sides will cancel giving -1=0 which is absurd.
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