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What is the inverse of the given relation? y = 3x + 9 A. y = 1/3x + 3 B. y = 3x - 3 C. y = 3x + 3 D. y = 1/3x - 3
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Interchange the x and y and solve the resulting equation for y
i'm sorry i don't understand?
Put y where x is and x where y is.
x=3y+9
Now solve for y
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how do i do that? subtract 9 from both sides?
so how would i set all that up?
First, you need to interchange x and y in the given relation which would give you: x = 3y + 9 now x - 9 = 3y or 3y = x- 9 Therefore, y = (1/3)x - (9/3) y = (1/3)x - 3 Got it? :)
ohhh okay , thank you!! :)
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