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Half-Angle Identities: How would i solve sin(13pi/12)? Don't know what to do with the 13, since it is not part of the Unit Circle.
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Consider that 13 = 9 + 4
9pi/12 and 4pi/12 should be on the unit circle.
you can use the identity: \[ \sin(x+y) = \sin(x)\cos(y) + \sin(y)\cos(x) \]
i have to do that with in the equation? the sinx/2
Okay then try the halfangle formula.
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