Question

math question help??

Answer 1

Perimeter of 21

Answer 2

shoot

Answer 3

so 3x+(5/4)y+((5/4)y = 21 ...

Answer 4

10/4 y + 12/4y = 21 ... 22/4y = 21 ... i think.. geometry yumm

Answer 5

What are you solving for?

Answer 6

Im solving for x and y sorry forgot to put that in!

Answer 7

Is that all the info you are given?

Answer 8

yes thats it

Answer 9

You can only solve for two variables, x and y, if you have two independent equations.
Here you can only write one equation:
(5/4)y + (5/4)y + 3x = 21
The sum of the lengths of the three sides is the perimeter.
You have one equation and two unknowns, you can't find the values of x and y.
(10/4)y + 3x = 21

Answer 10

He's good lol

Answer 11

oh okay thank you! so those equations are for just x? or y to?
2DCaddi123 lol i kno right

Answer 12

Is this part of a problem that has 2 triangles? The other one has perimeter 14? and sides y, y, and x?

Answer 13

Yes that was my other one

Answer 14

They are both part of one single problem. You need to have both triangles together in one problem to be able to solve because the other triangle gives you a second equation with x and y.

First triangle: x + y + y = 14
Second triangle: 3x + (5/4)y + (5/4)y = 21

x + 2y = 14
3x + (10/4)y = 21 or 3x + (5/2)y = 21
Multiply 2nd eq by 2:
6x + 5y = 42

Now rewrite the two equations:
x + 2y = 14
6x + 5y = 42

Multiply top eq by -6, and write second eq below:
-6x - 12y = -84
6x + 5y = 42

Now add the equations:
-7y = -42
y = 6
Now substitute y = 6 into original first eq:
x + 2y = 14
x + 2(6) = 14
x + 12 = 14
x = 2

Answer: x = 2, y = 6

Answer 15

Thank you! are you any good and english by any chance?

Answer 16

You're welcome, and no.

Answer 17

Kk ty anway c: