completely factor the polynomial
3x^3+9x^2=3X +9

Question

completely factor the polynomial 
3x^3+9x^2=3X +9

campbell_st · Answer

well on the left hand side of the equation you can factor out

$$3x^2$$

so you get 

$$3x^2(x + 3)$$

on the right hand side of the equation you can factor out 3

$$3(x + 3)$$

so you have 

$$3x^2(x + 3) = 3(x + 3)$$

there is still a bit to do but hopefully this will help you get to the answer

vortish · Answer

IT does thanks

vortish · Answer

now im stuck

campbell_st · Answer

ok.. so rewrite the equation as 

3x^2 (x + 3) -3(x +3) = 0

so you get 

(x +3)(3x^2 - 3) = 0

factor out the 3 in the 2nd set of brackets and you have 

3(x + 3)(x^2 -1) = 0

now the 2nd set of brackets in the difference of 2 squares which you'll need to factor..

hope it makes sense.

anonymous · Answer

so now u factor that last bracket :) 

make it into ( ) ( ) form :)