Question

integration problem, please help :)

Answer 1

\[\int\limits_{}^{}\frac{ 1 }{ (1-6x)^4 }\]

Answer 2

whoops, forgot to write dx afterwards

Answer 3

U subbbbbbb \:D/

\(\large u=1-6x\)
Taking the derivative of U with respect to X gives ussssssssss,
\(\large du=-6dx\) right?

Hmmm but we don't have a -6 in our problem here... maybe we can fix that.
Divide both sides by -6 giving us, \(\large -\frac{1}{6}du=dx\).

Answer 4

\[\large \int\limits \frac{1}{u^4}\left(-\frac{1}{6}du\right)\]Understand how we did that? :O