What are the x- and y- intercepts of the following equation: y = -0.05x + 16
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Question

What are the x- and y- intercepts of the following equation: y = -0.05x + 16
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aravindg · Answer

$$\huge \text{WELCOME TO OPENSTUDY !}$$

aravindg · Answer

Try to write the equation in form 

x/a+y+b=1

aravindg · Answer

then a will be x intercept and b will be y intercept

anonymous · Answer

x intercept is the point that lies on the x-axis and is when y=0
y intercept is the point that lies on the y-axis and is when x=0

anonymous · Answer

thank you :]

anonymous · Answer

the y intercept is what you get if $x=0$ your equation is written in the "slope intercept" form $y=mx+b$so the y intercept is displayed for you as $b$ in your cases $16$

anonymous · Answer

so it would be (0, 16), (32, 0) ?

anonymous · Answer

the first one is right, i don't think the second one is
if it is $.05$ and not $.5$ then you are off by a factor of 10

anonymous · Answer

$$ y = -0.05x + 16 $$$$0=-.05x+16$$
$$.05x=16$$
$$x=16\div .05=1600\div 5=320$$

anonymous · Answer

(320, 0) ?

anonymous · Answer

thank u

anonymous · Answer

Solve 3(x - 2) > 4(2x + 11). 
can u help me with this one please ?