Question

In quadrilateral ABCD, m∠ACD = 2x + 4 and m∠ACB = 5x-8. For what value of x is ABCD a rhombus.

Answer 1

In a rhombus, each diagonal bisects a pair of opposite angles.

Answer 2

I keep getting 6 at the very end, is that correct?

Answer 3

No, x is not 6. How did you set up your equation?

Answer 4

I'm doing what my teacher says, solve both equations for x then adding them together. I did just redo it the way he told me to and i got 5

Answer 5

Show me the equation you are trying to solve.

Answer 6

2x + 4=2 + 5x-8=3 then 3+2=5

This is what my teacher taught me but it just doesnt seem right

Answer 7

Since the diagonal bisects the opposite angles, that means m<ACD = m<ACB, which means:
2x + 4 = 5x - 8
This is the equation you must solve.

Answer 8

4

Answer 9

Correct

Answer 10

You should be a teacher.

Answer 11

Thanks. I hope you understood the problem. You need to take the understanding of the geometry part to then handle the algebra part

Answer 12

@jolenewhite.2000