Question

find the derivative of:
y= te^-t^2

Answer 1

use the product rule :
y = u v
y ' = vu' + uv'

Answer 2

@RadEn was your solution:
e^-t^2 - 2t ?

Answer 3

in this case,
u=t ---> u' = ... ?
v=e^(-t^2) ---> v' = ... ? (here, use the chain rule)

Answer 4

@RadEn
u' = 1
v' = e^(-t^2) . -2t . In e
I hope that makes sense..