Describe the differences between the graph of y = – ¾(x – 6)² + 4, and the standard position graph of y = x². The graph of y = x² has had four transforming actions done to it to arrive at: y = – ¾(x – 6)² + 4 ① the factor –¾ in front of the bracket is really composed of two transformining actions: – 1 and ¾. The "– 1" factor flips the standard graph over the x-axis serving as a mirror line ② the ¾ factor is a vertical shrinking factor; each point of the standard graph has its y-co-ordinate squashed to ¾ of what is was originally. example, (2, 4) is on the original graph of y = x²; (2, ¾of4

Question

Describe the differences between the graph of y = – ¾(x – 6)² + 4, and the standard position graph of y = x².  The graph of y = x² has had four transforming actions done to it to arrive at: y = – ¾(x – 6)² + 4  ① the factor –¾ in front of the bracket is really composed of two transformining actions: – 1 and ¾. The "– 1" factor flips the standard graph over the x-axis serving as a mirror line  ② the ¾ factor is a vertical shrinking factor; each point of the standard graph has its y-co-ordinate squashed to ¾ of what is was originally.  example, (2, 4) is on the original graph of y = x²; (2, ¾of4

aravindg · Answer

$$\huge \text{WELCOME  TO OPENSTUDY!} $$