Question

Could someone explain this? I kinda forgot how to do it. A particle is moving along the curve y = sqrt(x).As the particle passes through the point (9, 3), its x-coordinate increases at a rate of 7 cm/s. How fast is the distance from the particle to the origin changing at this instant?

Answer 1

so i know that dx/dt = 7 cm/s
looking for ds/dt= ?
d^2 = sqrt[(9-x)^2+(3-sqrt(x))^2] (i think?)