Question

Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?

Answer 1

SOMEONE HELP

Answer 2

what are the possible answers?

Answer 3

we need the "possible combinations"

Answer 4

I agree!

Answer 5

10 dark bars and 15 milk bars
12 dark bars and 12 milk bars
14 dark bars and 18 milk bars
6 dark bars and 21 milk bars

Answer 6

Jk :P

Answer 7

thank you. <3

Answer 8

all you gotta do is plug the numbers into the equation which will give u the answer of C

Answer 9

youre wrong actually..

Answer 10

14 dark bars and 18 milk bars

that's he correct answer

Answer 11

6(14)+4(18) DOES NOT = 120

Answer 12

the*

Answer 13

your right haha good job. sorry, and thanks