3/2 times 1/4 ≥ 1/2 (2x+1) ........... Plss answer it ... i cant do this ....
\[\frac{3}{2} \times \frac{1}{4} \ge \frac{1}{2}\times (2x+1)\]First, what is 3/2 x 1/4?
is equals to 3/8 and then ?
Right. Now distribute the 1/2 on the right side to everything inside the parenthesis.
(2x+1) = 1/2 ????
i can't understand ?
Yes you can.\[\frac{1}{2} \times (2x+1)=\frac{1}{2}\times 2x + \frac{1}{2}\times 1\]
how about 3/8 ?
We'll come back to that soon. For now, finish simplifying the right side of the equation.
how ....?
Well, what is\[\frac{1}{2} \times 2x\]?
2x X 1 = 3x ... 2x X 2 = 4x
how to multiply by fraction ?
If you have\[\frac{a}{b} \times \frac{c}{d}\]when you multiply them together you get\[\frac{a \times c}{b \times d}\]
And if there is nothing under one of them (say like for the number 2) then you pretend there is a 1 underneath of it.
the answer it 2x/2
But what is 2/2?
how about the x ...?
\[\frac{2x}{2}=\frac{2}{2}x\]if that helps
ahhh ... i knew it ..
and then whats the next process ?
Well we have\[\frac{3}{8} \ge x+\frac{1}{2}\]now. Subtract 1/2 from both sides.
2/6
No.\[\frac{3}{8}-\frac{1}{2}=\frac{3}{8}-\frac{1}{2} \times \frac{4}{4}=\frac{3}{8}-\frac{4}{8}=\frac{3-4}{8}\]You have to make sure that the denominators are the same, and then you add or subtract the numerators.
-1/8 ???
Yes!
ohhh .... thanks ....
So now you have\[\frac{-1}{8} \ge x\]and that's it!
owkey ... but the 8 is not negative ?
Well, if it was, then you would have\[\frac{-1}{-8}=\frac{1 \times -1}{8 \times -1}=\frac{1}{8} \times \frac{-1}{-1}=\frac{1}{8}\]
owkey ... thanks ... very much ..
You're welcome.
how about checking ?
Checking?
yess ...?
You mean to make sure you have the right answer? You could take -1/8 and plug it in for x in your original equation. When you simplify both sides they should be the same.
how ... 3/2 X 1/4 > 1/2 X 2 (-1/8) +1
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