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Factor the expression: x3 + 2x2 - 3x - 6
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x^3 + 2x^2 - 3x - 6 x^2(x + 2) - 3(x + 2) (x^2 - 3)(x + 2) (x^2 - 3)(x + 2) or (x + √3)(x - √3)(x + 2)
\[\Large x^3 + 2x^2 - 3x - 6\] \[\Large (x^3 + 2x^2) + (-3x - 6)\] \[\Large x^2(x + 2) -3(x + 2)\] \[\Large (x^2-3)(x + 2)\]
So what would I put down as the answer?
jim is right
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I would stop at \[\Large (x^2-3)(x + 2)\] instead of keep going to get \[\Large (x-\sqrt{3})(x+\sqrt{3})(x + 2)\] because most books I've seen factor over the rationals
Thank ya'll :)
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