Help Please:
Here is the problem:
find the slope intercept form of the equation of the line passing through the pts.
(5,-1),(-5,5)
I used the 2pt form which is: y-y1=(y2-y1/x2-x1)*(x-x1)
The end answer is: y=-3/5x+2
I have solved all the way to:
y=-3/5(x-5)-1
I can't figure out how to solve the rest of it to get
y=-3/5x+2
Please help. I've been working on this problem for 2 hours.

Question

Help Please:
Here is the problem: 
find the slope intercept form of the equation of the line passing through the pts.
(5,-1),(-5,5)
I used the 2pt form which is: y-y1=(y2-y1/x2-x1)*(x-x1)
The end answer is: y=-3/5x+2
I have solved all the way to:
y=-3/5(x-5)-1
I can't figure out how to solve the rest of it to get 
y=-3/5x+2
Please help. I've been working on this problem for 2 hours.

anonymous · Answer

$$y=-\frac{3}{5}(x-5)-1$$
$$y=-\frac{3}{5}x+3-1$$
$$y=-\frac{3}{5}x+2$$

anonymous · Answer

Where did the +3 come from?

jim_thompson5910 · Answer

-3/5 * -5

-3/5 *  (-5/1)

(-3 * (-5))/(5 * 1)

15/5

3

So -3/5 * -5 = 3

anonymous · Answer

oh! Thank you so much for explaining that to me,