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Mathematics 18 Online
OpenStudy (anonymous):

Can you help me solve this problem for the roots by using the quadratic formula? 2(6 - x) = x(x + 5)

OpenStudy (anonymous):

I don't know how to use the quadratic formula..

OpenStudy (anonymous):

As well as I'd like.

OpenStudy (anonymous):

start with \[2(6 - x) = x(x + 5)\] \[12-2x=x^2+5x\] \[x^2+7x-12=0\] then go form there

OpenStudy (anonymous):

@diamondsparkles5892 do you have an answer?

OpenStudy (anonymous):

ok, here: starting from where satellite left off, x^2 + 7x - 12 = 0 which means that a = 1, b = 7, and c = -12 if you dont know the quadratic equation already, it's |dw:1358397439146:dw| so now just plug in the values. |dw:1358397599665:dw| and then simplify it. |dw:1358397665084:dw|

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