re write in vertex form
Y=x^2-6x+4

Question

re write in vertex form 
Y=x^2-6x+4

anonymous · Answer

Y=x^2-2(3)x +9 +4 -9
y+9=(x-3)^2
vertex 3,-9

anonymous · Answer

completely confused

tkhunny · Answer

Completely the Squarely!  Think on this idea: $(a+b)^{2} = a^{2} + 2ab + b^{2}$.  It's particularly the b-part that should sink into your brain.

anonymous · Answer

listen im sorry but i have a hard time in algebra 2  im pretty sure this explination is good but i dont understand any of this  because im homeschooled and i have a hard time in math and im failing even though i have straight a's in every other class :(

tkhunny · Answer

??  You're supposed to think about it, not just suddenly manage to get it.  The study of mathematics should involve a thought process, not just a memorization process.

We have this: 

$x^{2} - 6x + 4$

How does that relate to:

$a^{2} + 2ab + b^{2}$

a in the second expression takes the place of xe in th first expression.  Then, how does this:

$x^{2} - 6x + 4$

Relate to this?

$x^{2} + 2xb + b^{2}$

Seriously, stare at those b-parts...

If "2xb" relates to "-6x", then 2b = -6 and b = -3.

Now what?  We are learning to "Complete the Square"!  What could be more fun?!

anonymous · Answer

this kinda makes sense lbut i still cant figure it out

tkhunny · Answer

You have '$b$' and you need '$b^{2}$'.  How do you propose we should find $b^{2}$?

anonymous · Answer

b*b

anonymous · Answer

what i dont understand is the 2ab and the 6x