Question

Find a cubic function with the given zeros. sqrt7, -sqrt7, -4

Answer 1

this is easy.
you want an equation which spits out 0 when x= sqrt7, -sqrt7 and -4.
i.e the roots of the equation are
x=sqrt7
x=-sqrt7
x=-4

this implies that
x-sqrt7=0 ..........1
x+sqrt7=0 .........2
x+4=0 ..........3

Now you get the equation by just multiplying 1,2 and 3.
i.e. \((x-\sqrt{7})(x+\sqrt{7})(x+4)=0.\)

Answer 2

you can simplify that if you want.

Answer 3

would it be f(x) = x^3 + 4x^2 - 7x - 28?

Answer 4

idk you tell me...all you have to do is multiply those terms. I haven't simplified it.