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solve 3√x-2+7=28
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Is that actually \[3\sqrt{x-2}+7 = 28\]?
that's inside the square root?
what's*
thats what the problem is
In any case, the route is the same: move everything outside of the radical to the other side, square both sides, solve for x.
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Yeah, what's inside the root. and is it 3 * the root, or is it the cubed root?
The equation button is pretty to use, and it saves a lot of wasted time if you show the problem correctly, hint hint :-)
x-2+7=28 is in the square root
Putting the equals sign inside the square root doesn't make any sense.
well thats what it is on my exam
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