Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Question in comments...plz help

OpenStudy (anonymous):

Ok.

OpenStudy (anonymous):

\[a^4-29a^2+100<0\]

OpenStudy (anonymous):

i really need an explanation or showing of work.

OpenStudy (anonymous):

Holy chiznets. What type of math is this. Geometry, Triginometry, Calculus, Algebra, etc.

OpenStudy (anonymous):

Algebra

OpenStudy (anonymous):

1 or 2

OpenStudy (anonymous):

2

OpenStudy (anonymous):

quadratic inequalities

OpenStudy (anonymous):

Can't help you their. I'm just getting out of Geometry. I take Algebra II starting Tuesday. Sorry laddy.

OpenStudy (anonymous):

it's okay, thanks for trying

OpenStudy (anonymous):

I aced Algebra I though I know that much. In my day we didn't have all this fancy schmancy stuff(I'm only 14). I don't know nuttn bout dis der Aljero!

OpenStudy (anonymous):

I gotta kick outta that

OpenStudy (anonymous):

im 14 also...

OpenStudy (anonymous):

i need to find the solution set of the inequality.

OpenStudy (anonymous):

Will you give me a medal for trying?? :DD

OpenStudy (anonymous):

Maybe...

OpenStudy (anonymous):

Can you please solve the quadratic equation first? I mean to find that value of a when the equation is 0

OpenStudy (anonymous):

Tehehe.

OpenStudy (anonymous):

ya im pretty sure it's \[a^2-5a-2a+10\] After it's been factored it's \[(a-5)(a-2)(a-5)(a-2)\]

OpenStudy (anonymous):

Not quite..

OpenStudy (anonymous):

No repeated factors in this case.

OpenStudy (anonymous):

so just \[(a−5)(a−2)\] ?

OpenStudy (anonymous):

There are four factors :)

OpenStudy (anonymous):

so \[(a−5)(a−2)(a+5)(a+2)\] ?

OpenStudy (anonymous):

Bingo!

OpenStudy (anonymous):

|dw:1358566081932:dw| So, the graph is like this (sorry for my poor drawing..) In what region does the function have a value less than 0?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!