Question

Find all solutions in the interval [0, 2π).

2 sin2x = sin x

Answer 1

sin^2x*

Answer 2

Subtract sin x from both sides and factor out sin x. Then set each factor equal to 0 and solve.

Answer 3

Okay, thanks. So you factor and set it to 0?

Answer 4

yes. Set each factor to 0

Answer 5

I'm sorry, I had a blank moment, how do you factor? Once again, so sorry about the stupid question.

Answer 6

\[2 \sin^{2} x = \sin x\]
\[2\sin^{2} x - \sin x = 0\]
\[\sin x (2 \sin x - 1) = 0\]

Answer 7

Okay, I did it correctly, thought I did it wrong. :P

Answer 8

Thanks to the both of you.

Answer 9

yw