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Mathematics 8 Online
OpenStudy (anonymous):

6x-3=5x-5

OpenStudy (konradzuse):

Any idea how to start this off?

OpenStudy (anonymous):

Isolate all the x's into one side. Then combine like terms.

OpenStudy (anonymous):

no

OpenStudy (konradzuse):

Okay, so like Ryan said, you want to get the x's on one side, and then get a # = to x on the other side.

OpenStudy (anonymous):

transpose 5x to the other side so as -3 to the other side also. then combine like terms. :)

OpenStudy (konradzuse):

so first we can either take the 5x or the 6x and put it onto one side, then solve for 5 and the 3, or switch it around.

OpenStudy (konradzuse):

\[(6x−3=5x−5)==-5x (6x−3=5x−5)-5x\]

OpenStudy (konradzuse):

do you see what I did so far? I'm taking (-5x) and adding it to both sides, or subtracting 5x from both sides, same thing.

OpenStudy (konradzuse):

now what do we get?

OpenStudy (anonymous):

I think he just wants an answer....

OpenStudy (anonymous):

How about a similar problem: 10x - 5 = 8x - 9 1. Get all x's on one side: -8x -8x 2x - 5 = - 9 2. Isolate x (get it alone) + 5 + 5 (Undo +/- first) 2x = 4 x = 2 (Divide both sides by 2) Your procedure is the same.

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