Question

In the figure, ABCD is a cyclic quad. BD is the angle bisector of 13 years ago

Answer 1

@hartnn & @mathstudent55 would you kindly help me?

Answer 2

did u get the first part ?

Answer 3

which part exactly, you have difficulty with ?

Answer 4

all..

Answer 5

ok, since BD is the angle bisector of <ABC
< ABD = <CBD
---> arc AD = arc CD
--->AD=CD

Answer 6

wow...powerful....got it

Answer 7

in a cyclic Quadrilateral,
A+B = C+D =180
A =y
C = <BCD = 180 -y

Answer 8

ok ?

Answer 9

ok

Answer 10

in triangle, BDC, do you know angle CBD = ??

Answer 11

35

Answer 12

yes, so since angles in a triangle =180 ,
can you find angle CDB

Answer 13

y-35?

Answer 14

good :)

Answer 15

what about angle ADB =.. ?

Answer 16

180-35-y
145-y?

Answer 17

correct,
now for AB=CB
<ADB =<CDB
can you find y from here ?

Answer 18

y-35=180-y?
2y=215
........

Answer 19

y-35 = 145-y
right ?

Answer 20

<BCD=180-y...
<BDC=y-35

Answer 21

how 180-y ?
<ADB = 145-y

Answer 22

<BDC...

Answer 23

oh my god. I forgot to draw the picture....