Question

here is a list of numbers:
0,3,5,7,12,29.
find three numbers from the list with the range double the median.

Answer 1

the median as of now is (5+7)/2 = 6
so range = 12.
three numbers from the list with the range 12 ? sorry, i didn't get the question....

Answer 2

I guess 12 is the maximum value of the range ?

Answer 3

i dont get it either
i know the median and range

Answer 4

range = maximum value in list - minimum value in the list.

Answer 5

29-0

Answer 6

?

Answer 7

29-3?

Answer 8

i think its
range = maximum value in list - minimum value in the list+1.
= 29-0 +1 = 30.

Answer 9

not +1

Answer 10

26

Answer 11

No, just max - min.

Answer 12

min value = 0
so, range = 29

Answer 13

the range is definatly 24 and the median is 12

Answer 14

0 is not a value

Answer 15

\[0 \] is not a value

Answer 16

median is the middle value, when the elements are in ascending/descending order.
if there are even number of elements, then there will be 2 middle values and median = average of those 2 values,
so median = (5+7)/2 =6
and 0 is considered as element and its min.

Answer 17

But we need three numbers from this list, not the list itself.

Answer 18

thats why i didn't get the question.....

Answer 19

Obviously, \(0\) can't be in the list.

Answer 20

But you can try 5,12 and 29...

Answer 21

no it gives the infomation that range=24 and median=12
i understand how to calculate range and median and dont understand why it says that the abover is the range and median

Answer 22

0 is in the list

Answer 23

I mean, \(0\) can't be amongst the three numbers we wanna choose.

Answer 24

oh yeah

Answer 25

that..yes.

Answer 26

We just have to choose three numbers from the list such that the three numbers have their median = 12 and range = 24.

Answer 27

So observe,\[29 -5 = 24 \]

Answer 28

how can there be a median and range of a single number

Answer 29

then 5,12,29 is eligible list.

Answer 30

So the middle element can be 12.
And our set is 5,12,29

Answer 31

how?

Answer 32

oh i get it

Answer 33

5,12,29.

The median is the middle number.
Range = max - min.

Answer 34

there can be a median and range of a single number, but its not the case here.

Answer 35

we have to choose three numbers!

Answer 36

what about the 3

Answer 37

No, we can choose ANY three numbers.

Answer 38

5 12 29?

Answer 39

Yes

Answer 40

but in the end there can only be 3 correct numbers

Answer 41

what about 3

Answer 42

Yes, and these are the three correct numbers... :|

Answer 43

0 3 5 (emphasis on 3)

Answer 44

Is 5 - 0 the double of 3?

Answer 45

@ParthKohli i know

Answer 46

no its 5

Answer 47

3x2=6

Answer 48

5-0 =5

Answer 49

So 0,3,5 is not a valid list...

Answer 50

The only valid list is 5,12,29.
Deal with it!

Answer 51

no whay did you not do 29-3

Answer 52

Hmm?

Answer 53

lol :P
because 0 is minimum .

Answer 54

0 is not a value is it but its got nothing to do with 3

Answer 55

0 is a value, valid element of list and minimum element of this list
so range = 29-0 = 29

Answer 56

No, my point was that 0 could not have been in the three numbers because in that case, we'd wanna have something in the form \(0,n,2n\).

There are no two numbers in the form \(n\) and \(2n\).

Answer 57

In the list, that is.

Answer 58

oh yeah

Answer 59

and we didn't do \(29 - 3\) for the range because our list of three numbers is \(5,12,29\)

Answer 60

If we had picked \(3\) and \(29\), then the median would have been \(13\) which is not the member of our set... :-P

Answer 61

yeah i get it

Answer 62

;-)

Answer 63

thnkx