Question

Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

y = 2x + 6
y = -1/2x + 3
y = −-1/2x + 6
y = 2x + 3

Write the equation of the line that is parallel to the line 3x − y = −3 and passes through the point (4, −2).

y = -1/3x − 6
y = −1/3x − 14
y = 3x − 6
y = 3x − 14

Answer 1

perpendicular

m1 * m2 = -1

Parallel

m1 = m2

Answer 2

Consider y=2x+6
Gradient of the above line = 2
Therefor, gradient of any line perpendicular to the above line = -1/2

Since the considered perpendicular line is passing through (6,3) ;
the required line ,
(y-3) =(-1/2)*(x-6)
2y+x-12=0

You can do the next question similarly

Answer 3

ok i wanna try

Answer 4

for ur question 1

Answer 5

@shamim I just need the answer to #2 now sorry

Answer 6

ur given equation of line is y=2x+2

Answer 7

ok

Answer 8

ur given line of equation is 3x-y=-3

Answer 9

or,y=3x+3

Answer 10

so the slope of ur line is m=3

Answer 11

and the slope of a parralel line is also m=3

Answer 12

and this parallel line will go through a point (4,-2)

Answer 13

I don't it to be explained, sorry, I just need the answer.. and I need it QUICK. Sorry

Answer 14

so the equation of ur parralel line will be
y-(-2)=3(x-4)

Answer 15

answer will b
y=3x-14