Which of the following is not an equivalent form of the compound inequality x - 1 10 x -2 A number line with an open circle on -11, shading to the left, and an open circle on -2, shading to the right. A number line with an open circle on -11, an open circle on -2, and shading in between. x -2 or x

Question

Which of the following is not an equivalent form of the compound inequality x - 1 < -12 or x + 12 > 10 x < -11 or x > -2 A number line with an open circle on -11, shading to the left, and an open circle on -2, shading to the right. A number line with an open circle on -11, an open circle on -2, and shading in between. x > -2 or x < -11

texaschic101 · Answer

x - 1 < - 12 = x - 1 + 1 < - 12 + 1 x < - 11 x + 12 > 10 x + 12 - 12 > 10 - 12 x > -2 now we have x being less then -11 and greater then -2 ANSWER : a number line with an open circle on - 11, shaded to the left, and an open circle on -2, shaded to the right. This is saying that from -11 , shaded to the left, would take you to numbers -12, -13, -14,etc...and from -2 shaded to the right would take you to -1, 0, 1, 2, etc....so it does not match the inequalities.