tan x = sqrt( 1 - x^2 ) Find all solutions. I don't even know where to start?
\[\tan = \frac{ opposite }{ adjacent }\]
I know the definitions of the trig functions, I just don't know what to do with this radical sign I guess. Haha :)
niether do i... i dunno of elementary algebra technique ti start this.... what class is this for?
Well, if you know that it's opposite over adjacent then: |dw:1358793809884:dw| use pythagorean theorem to solve for hypotenuse and find what that gives you. Could it be π/3? π/6? π/4? ... and similarly, what quadrant it lies on.
@student1988 , can u answer my previous question?
Hey thanks abb0t, This makes much more sense now that I see it as a place on the circle. I got 2 - x^2 for the hypotenuse. However, I don't see where this is on the unit circle?
This is a review for calc class. Haven't done trig for awhile so I am reviewing, dpalnc.
the problem there is that "x" is an angle (according to the left side of the equation)... but on the right side, "x" is part of the expression for a side of the triangle....
only way i can think of doing this is by graphing calculator... or wolfram...
There's a way to write an equation for a function, but I've forgotten how.. :(
since this is from a calculus class, then maybe this can be solved numerically... like newton's method maybe? i don't think you can solve it analytically
I guess i'll ask the teacher then. Thanks guys
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