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Mathematics 8 Online
OpenStudy (anonymous):

See attachment.

OpenStudy (anonymous):

OpenStudy (mathstudent55):

<15 vertical angles

OpenStudy (mathstudent55):

<4 <1 alt int angles

OpenStudy (mathstudent55):

<4 <12 opp angles of parallelogram

OpenStudy (mathstudent55):

<12 <9 alt int angles

OpenStudy (mathstudent55):

<9 <7 vertical angles

OpenStudy (anonymous):

Wait....they only have to be equal to angle number 1. So i think we're done

OpenStudy (mathstudent55):

Yes, I know, but all these angles are congruent to angle 1. <15 is congr to <1 bec of vertical angles <4 is congr to <1 bec of alt in angles <12 is congr to <4 bec of opp angles of parallelogram, and since <4 is congr to <1, <12 is congr to <1 <9 is congr to <12 by alt int angles, so <9 is congr to <1 <7 is congr to <9 by vertical angles, so <7 is congr to <1

OpenStudy (anonymous):

Oh, I apologize. I didn't understand that that was why. Thank you so much for your help!

OpenStudy (mathstudent55):

You're welcome

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