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Mathematics 18 Online
OpenStudy (anonymous):

.

OpenStudy (mathstudent55):

When you have a right triangle with an altitude drawn to the hypotenuse, you get two more right triangles. All right triangles are similar.

OpenStudy (mathstudent55):

Part a. Call the distance from the beach to the parking lot x. Then in the upper right triangle, the ratio of long leg : short leg = 32:x Then in the smaller lower right triangle, the ratio long leg : short leg = x : 18 Since all the triangles are similar, the ratios of the lengths of corresponding sides are euqual, so 32:x = x:18, or 32/x = x/18 Cross multiply and solve for x. x = 24, which you have. Part b. You need the length of the long leg of the large right triangle, let's call it y. Remember all 3 right triangles in this case are similar. In the small lower right triangle, the long leg to the short leg ratio is: 24:18 In the largest trianlge, the ratio of the long leg to the small leg is: y:? We don;'t have that, but we can get it with the Pythagoras theorem. The small lower triangle has leg = 18 and leg = 24. We need the hypotenuse, z. 18^2 + 24^2 = z^2 z^2 = 900, so z = 30 Let's get back to: In the largest trianlge, the ratio of the long leg to the small leg is: y:30 So 24:18 = y:30, or 24/18 = y/30 Cross multiply and solve for y

OpenStudy (anonymous):

I got 40 for y

OpenStudy (mathstudent55):

Correct

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