PLEASE HELP!! write an equation in slope-intercept form for the line that passes through (0,6) and is parallel to the line given by y=2x+3 .
first sorry for my spelling
general linear equation y=mx+c m=gradient c=y-intercept perpendicular tells us that we have to use this formula m1 x m2 = -1 m1=gradient of equation given m1=2 m2=gradient of unknown equation we want to find 2 x m2 = -1 m2=-1/2 now substitute (4,6) and gradient m=-1/2 into the general equation y=mx+c to find the c value and then re-write the whole equation.
are we looking for a prendicular line or parrallel
perpendicular line, and this helps us figure out the unknown equation perpendicular to the one given.
if it is parrarllel then the slope is the same but prependicular you would use the negative recipcoral
yes that is correct.
in the equation he says that is is parralel to y=2x+3 so why did you solve for the prendicular form you could have used y-y1=m(x-xx1) you already have the slope which is 2
then wouldnt you plug in the points you have and then slove
0,6 y-6=2(x-0) y-6=2x y=2x+6
used my graphing calc and they were both parralel in a diganol way
medal if right
did yiu have any questions
no thanks
okay
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