What is the length of side x in the triangle below? A. 18.46 B. 28.48 C. 24.63 D. 21.21 E. 19.65 F. 24.04 (Picture below.)
SOH-CAH-TOA |dw:1359045969808:dw| You have the adjacent and hypotenuse, so we use cosine. cos = adj/hyp cos45 = 17/x
the given triangle can be drawn as |dw:1359046012943:dw|
use eqn which @jazy told
your post is blinking y
cos(45) = 17/x 0.707 = 17/x Multiply both sides by x. 0.707x = 17 Divide both sides by 0.707. x = 17 / 0.707 What do you get?
1377.69?
@tayluvsya what?
By the way, this calculator helps a lot with these kind of equations. My teacher recommended it. (: http://web2.0calc.com/
Marco divide 17 by 0.707.
your question was blinking it stopped never mind
Oh cool! Thanks @jazy. And I got 24.05?
Yeah you're right. (: Actually when I did cos(45) it was actually 0.7071. So 17 divided by 0.7071, rounded would be 24.04.
Ups, I rounded it wrong :p
No you got it right, I rounded too early in the process, sorryyyy! (:
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