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Mathematics 20 Online
OpenStudy (anonymous):

Can someone help solve this? If h(t) represents the height of an object above ground level at time t and h(t) is given by h(t)=-16t^2+11t+1 find the height of the object at the time when the speed is zero.

OpenStudy (anonymous):

1. Take the derivative of the height function to get a speed fuction. V(t)=-32t+11 2. Set the derivative equation to 0. and solve for t. 3. Using T=.34375 seconds. 4. Plug T into the height equation to get H=2.89 units. Assuming you're in a calculus class and if I set this up correctly that's how you solve this.

OpenStudy (anonymous):

Yes, Thank you. I see what I did wrong.

OpenStudy (anonymous):

no best response?

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