answer please?
A construction truck collides with the back of a subcompact car. Which vehicle has the larger change in momentum during the collision? (Points : 1) The small car has a larger change in its momentum. The huge truck has a larger change in its momentum. They have the same change in momentum. Neither one changes its momentum.
things with larger mass have more resistance to change in momentum during impacts -- they dont change alot.
so the small car correct?
what if it was velocity ?
thats what Im led to believe yes. think of it like a golf club and a golf ball; when the two objects meet, which one changes velocity the most?
momentum is equal to the product of mass and speed. spose we have a truck as 1000 mass and a car of 10 mass; it doesnt tell us that they car is moving, just that the truck hits it in the rear. the truck will slow down a little bit, but the car will speed up alot to equal out the equation
the golf club ?
lets say the truck is going a speed of 50 1000(50) + 10(0) = (1000+10)(new velocity) 50000 = 1010 (new velocity) 50000/1010 = new velocity = 49.5 so the trucks momentum is 1000(49.5) and the cars momentum is 10(49.5) the trucks momentum barely registered a change, whereas the car went from 0 to 495; thats a pretty big change in momentum
a golf club has a bigger mass than a golf ball; when the 2 connect, the golf ball goes speeding away and the club tends to barely slowdown in that example of mine
so the small car would have a larger change in velocity
you should post in the physics section, but see http://scienceworld.wolfram.com/physics/ConservationofMomentum.html momentum is conserved,
momentum of a system is conserved; but what about the individual parts within the system?
Which vehicle has the larger change in momentum during the collision? if one loses p, the other gains p
the car should have a larger change in velocity from the collision if im seeing this correctly :)
well thanks for helping me understand this :D
yes, p= mv and m is constant. so v must change. the truck's v will go down, but the car's v will go up more, so that M dv = m dv
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