Question

I have to solve for x in this equation:
3x^2-15x=4x^2-23x+15

Answer 1

Use some of your algebra tricks to subtract and combine like terms. I'll start you off i your first step: \[(4x^2-3x^2)-(23x-15x)+15 = 0\]
combine like terms. then factor out. You should get a nice polynomial in the form: \[ax^2-bx+c=0\]
[HINT: C = 15]
Remember to factor, you want to find TWO numbers that when multipled together give you c, but when added together, give you your "b" term.
That way you get two numbers\[(x \pm a)(x \pm b)= 0\]
then you have two functions that you can set equal to zero. You should get two x-values.

Answer 2

Thank you so much!