Question

If h(t) represents the height of an object above ground level at time t and h(t) is given by h(t)=−16t^2+14t+1. Find the height of the object at the time when the speed is zero.

Answer 1

Remember our ratio formula: speed = distance / time.

(Another hint: since 0/anything = 0, basically you're solving for h(t) when t = 0.)

Answer 2

the speed is the derivative of h(t)
dh(t)/dt=-32t+14
-32t+14=0
hence t=14/32
plug t=14/32 in h(t)
and you get
4,0625