I'm confused. I keep getting a weird fraction. Help on what I'm doing wrong or what I should do please?
{y = 5/2x}
{x + 3y = 3}

Question

I'm confused. I keep getting a weird fraction. Help on what I'm doing wrong or what I should do please?
{y = 5/2x}
{x + 3y = 3}

hero · Answer

If y equals a fraction of x, chances are, the result will also be a fraction.

anonymous · Answer

{y = 5/2x} {x + 3y = 3}
x+15/2x=3 * 2x
2x^2+15=6x
2x^2-6x+15=0
then D=36-4.15.2 < 0
hence your equations don't have real roots, only complex ones
if asked for real solutions just write that the system has none

hero · Answer

Here's an approach:

y = (5/2)x
y = (5x)/2

2y = 5x

x + 3y = 3
5x + 15y = 15

2y + 15y = 15
17y = 15

`y = 15/17`

2(15/17) = 5x
30/17 = 5x

`x = 6/17`

anonymous · Answer

and here's what's wrong with your approach you take it that its y=(5x)/2 and i think it's 5/(2x)

artfis · Answer

Makes more sense. How did you get the 2y + 15y = 15 after the 5x + 15y = 15?

hero · Answer

Because 2y = 5x, so you just replace 5x with 2y in the second equation.

hero · Answer

@mivanov, you guessed incorrectly.

artfis · Answer

@Hero Thank you very much.