Question

find f'(x): 6x^100 x 17x^-3

Answer 1

the power will have to be brought down
so 6x100 and the actual power will decrease by one so 100-1
it will be 600x^99 for the first part, try the second part yourself.

Answer 2

17 * -3? :O

Answer 3

yes but what about the power/exponent?

Answer 4

51x^-4

Answer 5

so right now it;s f(x)=600x^99+51^-4

Answer 6

51x*

Answer 7

yes that is correct.

Answer 8

You have to use the power rule, derivative of the first times the second, plus the derivative of the second times the first, giving you a final answer of
(6x^100)(-51x^-4)+(600x^99)(17x^-3)