Question

Use the max-min inequality to show that if f is integrable then f(x) ≤ 0 on [a,b] -> ∫ (from a to be) f(x) d(X) ≥ 0

Answer 1

seems unlikely

Answer 2

of \(f(x)\) is never positive, then neither is the integral

Answer 3

are you saying there is no way of showing it? or the question does not have a definite answer?