-10x^2-14x-4=0

Question

-10x^2-14x-4=0

mertsj · Answer

Are you supposed to solve that?

anonymous · Answer

I cant get passed the first factoring

asapbleh · Answer

There are a few ways into solving it, but there's some ways that always work, such like the quadratic formula. So the quadratic formula is $$x=-b \pm \sqrt{b ^{2}-4ac}\div2a$$.

anonymous · Answer

its a quadratic

mertsj · Answer

First factor out -2

mertsj · Answer

$$-2(5x^2+7x+2)=0$$

mertsj · Answer

Now factor the trinomial inside the parentheses

whpalmer4 · Answer

To factor the (5x^2+7x+2) part, you're going to have factors of the form
(5x+a)(x+b).  The 5x*x gets you the 5x^2, and a*b gets you the 2. Your only choices for a and b are the numbers 1 and 2.  Remember also that 5b + 1a has to add up to 7 for the 7x term, so that makes b = 1 and a = 2 the only choice.

(5x^2 + 7x + 2) = (5x + 2)(x+1) and our whole factored polynomial would be
-2(5x+2)(x+1) = 0.  The places where that equals zero are the places where any of the product terms (5x+2), (x+1) = 0.  Trivial to solve those, right?