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Suppose the function f is continuous on the closed interval [a b]. Under what conditions is the value of the definite integral of f on [a b] equal to the area of a plane region that includes the graph of f on [a b] as a boundary? Explain when the value of the definite integral is not equal to the measure of the area of such a plane region.
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Weird question, but when the function is negative, you end up getting negative values (and area is always positive), so I suppose you could say whenever the function isn't negative.
@wio do you know under what condition is it? and how to prove?
Basically if the function is ever negative in the interval \([a,b]\).
i need some proving please
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