Question

how do i find the domain of this problem 14/x^2-5x

Answer 1

Since you have x^2 - 5x as a denominator, and you can't have zero in the denominator, solve the equation
x^2 - 5x = 0
Then the domain is all real numbers except those values of x that make the denominator zero.

Answer 2

what about \[ \sqrt{x+6}\] divided by 6+x

Answer 3

The numerator allows -6 to be included, but the denominator does not, so the answer is the domain is all real numbers x, such that x > -6