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integration of (sin^5x)*(cos^3x)dx
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split cos^3 x = cos x * cos^2 x write cos^2 x = 1- sin^2 x then its easy to see that u = sin x du =cos x dx.
so do you leave sin^5x as it is
yes, then you'll use it... s^5 (1-s^2) c dx [s=sin, c=cos]
s^5 (1-s^2) c dx = (s^5 -s^7) cdx
ah i see how that tricked me i tried to think it was a half angle formula or something
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so, now can you solve that integral ?
yea i can thanks a lot bro
welcome ^_^
math not my best subject :P
it became my best subject, after lot of practicing :)
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1 question though can you split sin of x to solve also
yes,but that will be more complicated....but yes.
ah i see ty again
if i need help again asking you :P
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